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3 years ago

How can you use addition to find the distance between 4 and 7

Mathematics

1 answer:

solong [7]3 years ago

5 0

So you go 4 plus what equals 7 and then you get 3. 4+3 = 7

the distance between 4 and 7 is 3

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Anna and Carla are 9 miles apart on a path when they start moving toward each other. Anna runs at a constant speed of 4 miles pe

Sergio [31]

Answer:

The answer is 3 miles.

4+2=6 , 6-9=3

4 0

3 years ago

Help plsssssssssssssssssssssss I will give brainliest if right

Lady bird [3.3K]

Answer:

8000 (c)

Step-by-step explanation:

20x20x20=8000

6 0

2 years ago

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Which of the following scenarios MUST represent two independent events?

egoroff_w [7]

Answer: C) P(blue) = 70%, P(green) = 30%, P(blue and green) = 21%

Step-by-step explanation:

Given probabilities P(A) AND P(B) are independent, the probability that both events to occur is given by:

P(A)∩P(B)

thus from the example, independent events will be:

P(blue)=70%, P(green)=30%, P(blue and green)=21%

Because:

P(blue)∩P(green)=0.7×0.3=0.21=21%

7 0

2 years ago

Find the value of the variables please please help me out I will mark you the brainly! Please please

RSB [31]

Answer:

m = 54

Step-by-step explanation:

The secant- secant angle 20° is half the difference of the intercepted arcs, that is

$\frac{1}{2}$ (160 - 2m - 12) = 20° ( multiply both sides by 2 to clear the fraction )

- 2m + 148 = 40° ( subtract 148 from both sides )

- 2m = - 108 ( divide both sides by - 2 )

m = 54

4 0

3 years ago

Read 2 more answers

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

3 years ago