Answer:
I think so, but maybe if the schools are different they change.
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
Step-by-step explanation:
<u>Given:</u>
- I = 5% = 0.05
- t = 2 years
- Let the sum is x.
<u>Simple interest:</u>
<u>Compound interest:</u>
- CI = x*(1 + 0.05)² - x = 1.1025x - x = 0.1025x
<u>The difference is 230:</u>
- 0.1025x - 0.1x = 230
- 0.0025x = 230
- x = 230/0.0025
- x = 92000
<h3>
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>
➷ Multiply 4.6 by 4 to get the sum of the numbers after 5 was added:
4.6 x 4 = 18.4
^ This is the new total
Subtract 5 from this:
18.4 - 5 = 13.4
Divide this value by 3 to get the original mean:
13.4/3 = 67/15
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
Answer:
-3,7,17,27,37,47,57,67,77,87,97,107
Step-by-step explanation:
You add 10 to -3 which gives you 7. You continue adding. This sequence goes on forever. You just keep adding 10.
I hope this helps!
