Which ordered pair is a solution of the equation? -4x+7=2y-3

Mathematics

1 answer:

Anika [276]3 years ago

4 0

Answer:

(2,1) and (5,-5)

Step-by-step explanation:

I just truned it in and it was right.

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PLZ HELP ASAP RIGHT TRIANGLES

borishaifa [10]

The correct answer is: AB = 3.11

Explanation:
Since

$cos(\theta) = \frac{base}{hypotenuse}$ --- (1)
$\theta$ = 50°
base = 2

And hypotenuse = AB

Plug in the values in (1):
(1) => cos(50°) = 2/AB

=> AB = 2/0.643
=> AB = 3.11

6 0

4 years ago

Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$