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nadya68 [22]
3 years ago
11

Twice the difference of a number and 2 is 9

Mathematics
1 answer:
likoan [24]3 years ago
6 0
2(n-2)=9
That's the answer. U just set it up as it is written
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Please help! this is due today and this is the only question left!!
Soloha48 [4]

Answer:

13.73 sq mm

Step-by-step explanation:

Area of Square - Area of Circle = Area of Shaded Region

if radius of circle is 4 then diameter is 8

the diameter is the same as the length of each side of the square

so area of square = 8² or 64

Area of Circle = 16π

64 - 16π ≈ 13.73

7 0
3 years ago
2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

5 0
3 years ago
Solve for x<br><br><br><br><br> Thankyouhjg
Levart [38]
Omg no do not click the link it’s takes all you’re information people have been doing this on app
5 0
2 years ago
Please help me thanks
posledela

Answer:

I knwo you Ur Gae

Step-by-step explanation:

6 0
3 years ago
Find the 35th term in the arithmetic sequence: -10,-14,-18,-22,..
ivanzaharov [21]
The 35th term is -146 :)
3 0
3 years ago
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