How to show that a function is surjective?

Mathematics

1 answer:

photoshop1234 [79]2 years ago

6 0

Algebra formula based function

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Adam is going to cook a turkey for 14 people and wants to allow ¾ lb of turkey for each person.

Kobotan [32]

Missing info:
Turkey Sizes:
small - 2kg - 3.9kg 
medium - 4kg - 5.4kg 
large - 5.5kg - 7.2kg 
extra large - 7.3kg - 9.2kg 

Turkey Prices: 
Small / Medium - £5.99 per kg 
Large / Extra Large - £4.99 per kg

3/4 lb x 14 persons = (3*14)/4 = 42/4 = 10.5 lbs

1 lb = 450 grams

10.5 lbs * 450grams/lb = 4,725 grams

1 kg = 1000 grams

4,725 grams * 1kg/1000 grams = 4725 kg / 1000 = 4.725 kg.

4.725 kg is under the Medium size of the Turkey.

Medium sized turkey costs £5.99 per kg.

4.725 kg * £5.99 per kg = £28.30

A turkey would cost £28.30 for 14 people.

4 0

2 years ago

How to use the slope formula to find the slope of a line please help me!!!!!!!

stepan [7]

Answer:

Sweetie, it's easy. Let me explain.

The slope formula is (y2 - y1) (x2 - x1) you find the slope by putting the rise over the run. For example, if the point goes up 2 and right 3 your slope would be (2,3) and let's just say your next coordinate is (4,5) you would take the y, 5, from the second coordinate and subtract it by the y from the first coordinate, 3. So you would have 2 and you do the same with the x values. So your slope would be 3/2. Hope I helped at all.

Step-by-step explanation:

8 0

2 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is A. 5y^6

$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is D. 12xy^2

$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

3 0

2 years ago

Time Remaining 1 hour 52 minutes 27 seconds01:52:27

Vanyuwa [196]

Answer:

Is this an exam? looks like it

5 0

2 years ago

Convert 9.8 cm to mm. (please show the steps to how you did the problem.)

UNO [17]

Answer:

0.98