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3 years ago

11

What is the smallest whole number that will round to 80

1 answer:

Oxana [17]3 years ago

5 0

2? I think so if not I'm sorry

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What is 10 x 6 please answer assap

rosijanka [135]

60 that's the answer.

7 0

4 years ago

9.12cm<br> 10.36cm<br> 11.34cm<br> 12.61cm

Vinvika [58]

Tan80 = QR / RS
QR = 5.67 (2)
QR = 11.34

answer

<span>11.34cm</span>

8 0

3 years ago

Please answer this question!! 30 points and brainliest!

murzikaleks [220]

Answer:

D. 2x^2-7x.

Step-by-step explanation:

Lets write it out to make it easy to work with.

-x(-2x+7)

Multiply the -x out

2x^2-7x.

The answer is D

4 0

4 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

Please Tell me what the answer

Helga [31]

OK for number 3is 70because you add the number that they give you and then subtract 36 106 and you get your answer

3 0

3 years ago