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3 years ago

Which of the following are valid probability distributions?

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find the value of x to the nearest tenth!

sergij07 [2.7K]

Answer:

5.7

Step-by-step explanation:

sine cosine tangent

soh cah toa

sine = opposite/hypotenuse

so sin(35)= x/10

you can multiply 10 to both sides to get rid of the 10 denominator on the right leaving you with 10sin(35)=x

be sure your calculator is in degrees.

put that into a calculator leaving you with 5.7

5 0

3 years ago

The polynomial 3x ^ 3 - 16x ^ 2 + 31x - 20 the area of a trapezoidal desktop . Of the bases of the x ^ 3 - 5x the height of the

vaieri [72.5K]

Answer:

Step-by-step explanation:

Given:

Area = 3x^3 - 16x^2 + 31x - 20

Base:

x^3 - 5x

Area of trapezoid, S = 1/2 × (A + B) × h

Using long division,

(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x

= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh

= 2S/Bh - A/B

= (2S/B × 1/h) - A/B

Since, x^3 - 5x = B

Comparing the above,

A = 32x^2 - 92x + 40

2S/B = 6

Therefore, h = 1

6 0

3 years ago

the original price of the cell phone luc wants to buy 150 the phone is now on sale for $100 what is the percent phone discount

Ronch [10]

150-100 = 50

50/150 = 0.333 = 33.3% discount

8 0

3 years ago

Lynn is trying to determine how far away Student B is from the balloon. He decides to use the

kaheart [24]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the image that illustrates the scenario is not given.

However, I can deduce that the question is about a right-angled triangle.

So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.

For triangle A (solve for b)

Using cosine formula.

$\cos \theta = \frac{Adjacent}{Hypotenuse}$

$\cos 60= \frac{5}{b}$

Make b the subject

$b= \frac{5}{\cos 60}$

For triangle B (solve for b)

Using cosine formula.

$\sin \theta = \frac{Opposite}{Hypotenuse}$

$\sin 60= \frac{b}{5}$

Make b the subject

$b = 5\sin 60$

For triangle C (solve for b)

Using cosine formula.

$\tan \theta = \frac{Opposite}{Adjacent}$

$\tan 60= \frac{b}{5}$

Make b the subject

$b = 5\tan 60$

3 0

3 years ago

Read 2 more answers

MDE = 115 and mbc =42. Find m

Tju [1.3M]

This is what I found

7 0

4 years ago