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7nadin3 [17]
3 years ago
10

6 less than r Someone please help me with this

Mathematics
1 answer:
poizon [28]3 years ago
7 0

Answer:

6 less then r

refers to 6 less then whatever number is represented with r

If the (r) is blank you can take it as 0

in this case the answer would most likely be -6

that is if r is not given

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Given g(x) = -x + 3, solve for x when g(x) = -1.
cluponka [151]

Answer:

4

Step-by-step explanation:

It's ok! This is simple. Simply plug in your given values. Since g(x) = -1, plug that into the equation.

g(x) = -x + 3

g(-1) = -(-1) + 3

=1+3

=4

7 0
3 years ago
Help please im not sure
Lisa [10]

Answer:

the first and last

Step-by-step explanation:

its correct

4 0
3 years ago
Read 2 more answers
Find the 58"" term of the following arithmetic sequence,<br> 18, 23, 28, 33,
Anna11 [10]

Answer:

303

Step-by-step explanation:

So the equation to find a term is An=a1+(n-1)d

An represents the value of the number (n)

and n is the selective that you want

d is the difference between the first and second term which is 23-18=5, and you can see that adding 5 to the previous term gives the following term.

a1 is the first term in the sequence

so knowing all that now you can go back and inset all variables into the equation

An=18+(58-1)5

An=303

Hope that helps :)

Please give brainliest

6 0
3 years ago
16. Factor<br> 40y3 - 625
lina2011 [118]

Answer:

Step-by-step explanation:

prime factorization

40y³ = 2³×5y³

625 = 5⁴

Greatest common factor = 5

40y³ - 625 = 5(8y³ - 125)

Note that 8y³ - 125 is the difference of cubes.

8y³ - 125 = (2y)³ - 5³ = (2y-5)((2y)² + 2y·5 + 5²) = (2y-5)(4y² + 10y + 25)

40y³ - 625 = 5(2y-5)(4y² + 10y + 25)

4 0
3 years ago
How do you do this ?
Sedaia [141]
This is the answer
first you must eliminate the denominator and that you do with multiplication
then eliminate the number that is on the same side of the letter and that you do it by placing the same number but with a different sign and so you have the answer.

also there is the check.

6 0
3 years ago
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