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2 years ago

1. Calculate means to A. Estimate B. Solve C. Guess D. Use a calculator the po

Mathematics

2 answers:

IgorLugansk [536]2 years ago

7 0

Step-by-step explanation:

I think the best option there is solve

Alecsey [184]2 years ago

7 0

B. Solve

Could be D. However, you can calculate an answer without a calculator

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PLEASE help!!

dezoksy [38]

The answer is A. $3,362.57. You just multiply the amount deposited by .0265, then add the amount you get with the amount deposited. continue multiplying the .0265 by each total and keep adding and you get A.

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3 years ago

Please need help on this

yanalaym [24]

Answer:

the answer is 77

Step-by-step explanation:

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4 years ago

Student council raised $670 earlier this year. Then they held a raffle. In total they raised $1,350. Write an equation an solve

navik [9.2K]

R= money collected at the raffle.
670+r= 1,350. Subtract 670 from each side of the equation to isolate the variable. Once you do that, you get r= $680.

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3 years ago

Read 2 more answers

Find the volume of the solid generated by revolving the area bounded by y=x^2 and x-axis from [0,2] around the x-axis

lesya [120]

Answer: $\dfrac{32\pi }{5}\ \text{unit}^3$

Step-by-step explanation:

Given

The area is bounded by $y=x^2$ and x-axis from [0,2]

The volume generated for $y=f(x)$ when rotated about the x-axis in the interval [a,b] is

$V=\int_a^b\pi y^2dx$

Insert the values

$\Rightarrow V=\int_0^2\pi x^4dx\\\\\Rightarrow V=\pi \int_0^2x^4dx\\\\\Rightarrow V=\pi \left[ \dfrac{x^5}{5}\right]_0^2\\\\\Rightarrow V=\dfrac{2^5\pi }{5}\\\\\Rightarrow V=\dfrac{32\pi }{5}\ \text{unit}^3$

8 0

3 years ago

X^2 + x - 6 over x^2 - 7x + 10 <br> simplify fully

Natali [406]

$\frac{x^2+x-6}{x^2-7x+10}$

When you factor a quadratic ax² + bx + c, it becomes (x+m)(x+n), where mn = ac, and m+n = b.

In x²+x-6, we want to find two numbers that multiply to -6 and add to 1.
3 and -2 satisfy both of these criteria, so there are our factors.

$\frac{(x+3)(x-2)}{x^2-7x+10}$

In x²-7x+10, we want to find two numbers that multiply to 10 and add to -7.
-5 and -2 satisfy both of these criteria, so there are our factors.

$\frac{(x+3)(x-2)}{(x-5)(x-2)}$

The (x-2) cancels and we're left with

$\boxed{\frac{x+3}{x-5}}$

5 0

4 years ago