You are balancing an ionic compound. Let's call it: AB.
1 answer:
Answer:-
Explanations:- It is given that the charge for A is +2 and the charge for B is -3. The over all compound is neutral means the over all charge is zero. For making the over all charge zero, we need 3 positive ions and 2 negative ions. This makes a +6 charge for A and -6 charge for B and the over all charge is zero.
Also, if we think about the criss cross then charge of A becomes the subscript of B and the charge of B becomes the subscript of A.
So, the formula of the ionic compound is . In this compound the ratio of A to B is 3:2.
The balanced equation could be shown as:
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The question is incomplete, here is the complete question:
An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?
<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
......(1)
Given mass of oxalic acid = 0.5842 g
Molar mass of oxalic acid = 90 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated oxalic acid solution
are the molarity and volume of diluted oxalic acid solution
We are given:
Putting values in above equation, we get:
Now, calculating the mass of glucose by using equation 1, we get:
Molarity of oxalic acid solution = 0.0026 M
Molar mass of oxalic acid = 90 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
Hence, the mass of oxalic acid in final solution is 0.0234 grams