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artcher [175]
3 years ago
12

Determine the percent water in MgSO4*7H20?

Chemistry
1 answer:
Semmy [17]3 years ago
5 0

Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

Best regards!

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A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K
SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

<u>Explanation:</u>

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

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Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

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Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}

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Now, we have to plugin the above values in the above equation, we will get the temperature as,

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3 years ago
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Answer:

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Answer:

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