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3 years ago

6

270kJ are needed to keep a 75 watt light bulb burning for 1 hour. How many kilocalories are needed to burn this light bulb for 3

hours?

1 answer:

elena-s [515]3 years ago

8 0

Answer:

For 1 hour 75w light bulb requires 270 kj for burning

for 3 hours 75 w light bulb requires 270*3 = 810kj for burning

Explanation:

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Why are metals alloyed?

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Because alloys have qualities that are preferable to pure metals, almost all metals are utilised as alloys—that is, mixes of several elements. Alloying is done for a variety of purposes, the most common of which are to increase strength, corrosion resistance, or cost savings.

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2 years ago

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance. What is the total resistance?

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Answer:

17 ohms

Explanation:

Given that,

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance.

We need to find the total resistance of the circuit.

The equivalent resistance for series combination is given by :

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For 17 light bulbs, the equivalent resistance is given by :

$R_{eq}=R+R+....\text{upto 17 terms}\\\\R_{eq}=17R\\\\=17$

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3 years ago

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The pathway by which carbon is transferred from living organisms to the atmosphere is called:

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Answer:

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Explanation:

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3 years ago

When 4.15 grams of silver nitrate is reacted with 1.11 grams of iron(III) chloride, which best represents the amount of silver c

PolarNik [594]

Answer:

The mass of silver chloride produced = 2.202 g

Explanation:

Equation of the reaction is given below

3AgNO₃(aq) + FeCl₃(aq) ----> 3AgCl(s) + Fe(NO₃)₃(aq)

molar mass of AgNO₃ = 170 g/mol

molar mass of FeCl₃ = 233.5 g/mol

molar mass of AgCl = 143.5 g/mol

3 moles of silver nitrate reacts with 1 mole of iron (iii) chloride to give 3 moles of silver nitrate

4.15 grams of AgNO₃ = 4.15/170 = 0.0244 moles of AgNO₃

1.11 grams of FeCl₃ = 1.11/233.5 = 0.0047 moles of FeCl₃

mole ratio of AgNO₃ to FeCl₃ = 0.0244/0.0047 = 5 : 1

therefore, FeCl₃ is the limiting reactant

0.0047 moles of FeCl₃ reacting will produce 0.0047 * 3 moles of AgCl = 0.0141 moles of AgCl

0.0141 moles of AgCl = 0.0141 * 143.5 g of AgCl = 2.02 g of AgCl =

Therefore mass of silver chloride produced = 2.202 g

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3 years ago