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3 years ago

6

270kJ are needed to keep a 75 watt light bulb burning for 1 hour. How many kilocalories are needed to burn this light bulb for 3

hours?

1 answer:

elena-s [515]3 years ago

8 0

Answer:

For 1 hour 75w light bulb requires 270 kj for burning

for 3 hours 75 w light bulb requires 270*3 = 810kj for burning

Explanation:

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Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

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First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

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Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

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Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

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