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Yuki888 [10]
3 years ago
8

Fill in the table using this function rule y= 18-3x

Mathematics
1 answer:
Mashcka [7]3 years ago
4 0

Answer:

1:15 2:12 3:9 5:3

Step-by-step explanation:

All you have to do is plug in the # under the letter x , and plug it into the equation. For example 18 - 3 x 1 , is just saying what is 18 - 3 . Another example would be 18 - 3 x 2 . the equation is simply just 18 - 6 . Just plug in the x numbers in the equation. Hope my answer helped  , and good luck! : )

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Given: 3x - 5 = 4 (2x – 15)<br> Prove: x = 11<br> Statement<br> Reason
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Step-by-step explanation:

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4 Tan A/1-Tan^4=Tan2A + Sin2A​
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tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

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• expand the functions of 2<em>A</em> using the double angle identities

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• factor out sin(<em>A</em>) cos(<em>A</em>)

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• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
2 years ago
Samantha evaluates the expression -5.3 + 7.9 and gets an answer of 2.4
Sholpan [36]

Answer:

Step-by-step explanation:

To the evaluate -5.3+7.9

We get

2.6

Therefore the error

=2.6-2.4

=0.2

6 0
3 years ago
Read 2 more answers
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