If the satellite was placed in an orbit three times farther away, about how long would it take to orbit the Earth once? Answer i

Question

olasank [31]

3 years ago

5

If the satellite was placed in an orbit three times farther away, about how long would it take to orbit the Earth once? Answer i

n days, rounding to one significant figure.

Physics

2 answers:

tiny-mole [99] · Answer 1 · 2022-04-19T10:54:37+03:00

Since many satellites are categorized for the height of their orbits, I will choose the lowest with the earth that is a type of satellite LEO is a satellite that has an altitude of 320-800 km above the earth's surface.

LEO's satellite circulation speed reaches 27,359 km / h to circle the earth in 90 minutes. LEO Delay Time of 10 ms (Time of wave propagation from earth station to satellite and back to earth station) so if the satellite was placed in orbit three times farther away it's gonna take 800 km divided by 27,359 Km / h = 29 hours and multiplied by 3; 29-hour x 3 = 3 days 6 hour and 25 minutes

Further Explanation

Many satellites are categorized from above the height of their orbits, although satellites can orbit at any height. Low Earth Orbit (LEO): 300km - 1500 km above the earth's surface.
Medium Earth Orbit (MEO): 1500km - 36000 km.
Geosynchronous Orbit (GSO): about 36,000 km above the Earth's surface.
Geostationary Orbit (Geostationary Orbit, GEO): 35790 km above the Earth's surface.
High Earth Orbit (HEO): above 36000 km.

And there are following orbit is a special orbit that is also used to categorize satellites:

Molniya orbit, a satellite orbit with a 12-hour orbital period and an inclination of around 63 °.
Sun-synchronous orbit, orbiting a satellite with a certain inclination and height that always crosses the equator at the same local clock.
Polar orbit, a satellite orbit that crosses the pole

Learn More :

Satellite: brainly.com/question/9266911, brainly.com/question/2166099

Details :

Class: Senior High

Subject: Physics

Keyword: Satellite

uranmaximum [27] · Answer 2 · 2022-04-19T09:21:36+03:00

Kepler's third law is called the law of harmonies<span> which calculates the period and radius of orbit of a planet with the given dimensions and period of another planet. The comparison is proportional to the square of period and inversely proportional to the cube of the distance. Hence when the distance is placed three times the original ((3D)^3), the period should increase by sqrt of 27 times of 5.20 times the original period,</span>