Answer:
a) Beth will reach before Alan
b)Beth has to wait 20 min for Alan to arrive
Explanation:
let 'd' be distance b/w Los Angeles and San Francisco i.e 400 mi
considering ,
Alan's speed 
=50mph
Beth's speed 
=60mph
->For Alan:
The time required 
= d/= 400/50 => 8h
-> For beth:
The time required 
=> 6h 40m
Alan will reach at 8:00 a.m +8h = 4:00p.m.
Beth will reach at 9:00 a.m +6h 40m= 3:40p.m.
a) Beth will reach before Alan
b)Beth has to wait 20 min for Alan to arrive
Answer:
Explanation:
The average speed is given by the formula: 
The distance covered is 250m , and the time is 110s.
Replacing in the formula: 
Resulting in : 
.
The atom´s mass number is the "number of neutrons and number of protons (option B) in an atomic nucleus. It might determine the atomic mass os atoms. Because neutrons and protons are baryons, the mass number A is identical to mass number B as of the nucleus, atom or iron.
Answer:
equipment for the measurement of microwave L bands with a range between 1 GHz and 2 GHz.
Explanation:
The electromagnetic spectrum can be calculated with the relationship between the speed of light, its wavelength and its frequency.
c = λ f
For reasons of analysis and equipment used, it is artificially divided into ranges, with poorly defined limits and in some cases with overlaps between some.
For the case of analysis, f = 1.41 10⁹ Hz, we have the range called
* Microwave for f> 3 108 Hz to approximately f <3 1011 Hz
For the lower part of the frequency 3 10⁸ <f <3 10⁹ Hz we have UHF television channels and cell phones and military communications.
As the frequency observed by the researchers is in the UHF range, it is possible that they are using microwave equipment for communications, specifically equipment for the measurement of microwave L bands with a range between 1 GHz and 2 GHz.
Answer:
smaller acceleration, so lower change in velocity
Explanation:
To answer this question we examine the equation that relates mass with force and with acceleration: 
.
Since we want to know what happens to the acceleration, we solve for it in the equation: 
Notice that we are asked what happens when the force applied is the same, but now it is applied in an object with more mass (M).
We therefore would have to compare our initial form:
with the new one: 
wher the denominator is a larger quantity, therefore making our division/quotient smaller. Then, we conclude that the acceleration will be smaller, and therefore the change in velocity of the object will be lower.
