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Answer:
Initial velocity of the object, u = 5 m/s
Final velocity of the object, v = 8 m/s
Mass of the object, m = 100 kg
Time take by the object to accelerate, t = 6 s
Initial momentum = mu = 100 — 5 = 500 kg m sˆ’1
Final momentum = mv = 100 — 8 = 800 kg m sˆ’1
Force exerted on the object, F = mv – mu / t
= m (v-u) / t
= 800 – 500
= 300 / 6
= 50 N
Initial momentum of the object is 500 kg m sˆ’1.
Final momentum of the object is 800 kg m sˆ’1.
Force exerted on the object is 50 N.
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1) find speed (8.8 m/s)
2) find acceleration (38.7 m/s^2)
answer is about 38.7 m/s^2
If one of two interacting charges is doubled, the force between the charges will double.
Explanation:
The force between two charges is given by Coulomb's law

K=constant= 9 x 10⁹ N m²/C²
q1= charge on first particle
q2= charge on second particle
r= distance between the two charges
Now if the first charge is doubled,
we get 
F'= 2 F
Thus the force gets doubled.