Answer:
a) the maximum transverse speed of a point on the string at an antinode is 5.9899 m/s
b) the maximum transverse speed of a point on the string at x = 0.075 m is 4.2338 m/s
Explanation:
Given the data in the question;
as the equation of standing wave on a string is fixed at both ends
y = 2AsinKx cosωt
but k = 2π/λ and ω = 2πf
λ = 4 × 0.150 = 0.6 m
and f = v/λ = 260 / 0.6 = 433.33 Hz
ω = 2πf = 2π × 433.33 = 2722.69
given that A = 2.20 mm = 2.2×10⁻³
so
= A × ω
= 2.2×10⁻³ × 2722.69 m/s
= 5.9899 m/s
therefore, the maximum transverse speed of a point on the string at an antinode is 5.9899 m/s
b)
A' = 2AsinKx
= 2.20sin( 2π/0.6 ( 0.075) rad )
= 2.20 sin( 0.7853 rad ) mm
= 2.20 × 0.706825 mm
A' = 1.555 mm = 1.555×10⁻³
so
= A' × ω
= 1.555×10⁻³ × 2722.69
= 4.2338 m/s
Therefore, the maximum transverse speed of a point on the string at x = 0.075 m is 4.2338 m/s
3277.8 because wave speed is calculated by the equation Speed= wavelength • frequently
Answer:
The height of the package when it was released was 1102.5 meters
Explanation:
A package is dropped from a hovering helicopter
Dropped means the initial velocity of the package is zero
The package takes 15 seconds to strike the ground
Ignore the air resistance
We need to know the height of the package when it was released
, where h is the height of the package
from the ground, u is the initial velocity, g is the acceleration of gravity
and t is the time
u = 0 , t = 15 seconds , g = 9.8 m/s²


h = 1102.5 meters
<em>The height of the package when it was released was 1102.5 meters</em>
Answer: I believe it is, "New evidence was discovered that made scientists revise their ideas"
Explanation: I don't think that people can travel under the plates :D
Answer:11.59 J
Explanation:
Given
mass of Particle 
Initially Particle moves towards left 
Final velocity of Particle is towards Right 
According to Work Energy theorem
Work done by all the Forces=change in Kinetic Energy
Work done by Force
![W=\frac{69\times 10^{-3}}{2}\left [ 31^-25^2\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%2031%5E-25%5E2%5Cright%20%5D)
![W=\frac{69\times 10^{-3}}{2}\left [ 961-625\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%20961-625%5Cright%20%5D)
