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erik [133]
2 years ago
6

Based only on the information given in the diagram, which congruence

Mathematics
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer: HL, SAS, LL, SSS

Step-by-step explanation:

its that easy

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Describe how ∠PTQ and ∠QTS in the figure are related.
timurjin [86]

Answer:

their unrelated

Step-by-step explanation:

might look similar but very different from each other

8 0
3 years ago
50% of what number is 140
BlackZzzverrR [31]

Answer:35.71

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An architect designs rectangular flower garden such that the width is exactly 2/3 of the length. of 290 ft of antique picket fen
kramer

Length (L): L

width (w): (2/3)L

Perimeter (P) = 2L + 2w

               290 = 2(L) + 2(2/3)(L)

               870 = 6L + 4L

               870 = 10L

                87 = L

width (w): (2/3)L   = (2/3)(87)   = 2(29)   = 58

Answer: width = 58 ft, length = 87 ft



6 0
3 years ago
An architect is designing a house in which a 104 square foot room and a 130 square foot room share a wall what is the greatest p
Alla [95]
Both rooms share a common side whose dimension is unknown. Call it x.

Then, the area of both squares have x as common factor.

So, x is the greatest common factor of 104 and 130.

You should know how to calculate the greatest common factor of two integers.

Just find the prime factors and choose the common factors raised to the lowest exponent.

104 = (2^3) (13)

130 = (2) (5)(13)

=> the greatest common factor is 2 * 13 = 26, and that is the greatest possible integer length of the shared wall.

Answer: 26



8 0
3 years ago
'Polonium-210 is a radioactive substance with a half-life of 138 days. If a nuclear
Tatiana [17]

Answer:

  • <u>59.0891 g (rounded to 4 decimal places)</u>

Explanation:

<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.

Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:

  • A=A_0\cdot (1/2)^n

Where:

  • A is the amount that remains of the substance after n half-lives have elapses, and
  • A₀ is the starting amount of the substance.

In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:

  • 330 days / 138 days = 2.3913

Therefore, the amount of polonium-210 that will be left in 330 days is:

  • A=310{g}\cdot (1/2)^{2.3913}=59.0891g
5 0
3 years ago
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