Question

To estimate the length of the lake, caleb starts at one end of the lake and walk 95m. He then turns a 60° angle and walks on a new path and walks 8m more then arrives at the other end of the lake. Approximately how long is the lake?

Answer 1

Answer:

Length of the lake is 97.30 m

Step-by-step explanation:

We have given Caleb starts at one end of the lake and walk 95 m

So $d_1=95m$

And then he turns at an angle of 60°

So $\Theta =60^{\circ}$ and then again walk 8 m

So $d_2=8m$

We have to fond the total length of the lake , that is d

Total length of the lake is given by $d=\sqrt{d_1^2+d_2^2+2d_1d_2cos\Theta }=\sqrt{95^2+8^2+2\times 95\times 8\times cos60^{\circ}}=97.30m$

So length of the lake is 97.30 m