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labwork [276]
3 years ago
14

Graphing/function?? Help??

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:I'm sorry but I think you should explain A little more. I'm in algebra two and I'm a bit perplexed, not by the problem but what goes where

Step-by-step explanation:

Explain What the variables are and what they mean please!

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The sum of two consecutive mile markers on the interstate is 417417. Find the numbers on the markers
noname [10]

Hello from MrBillDoesMath!

Answer:

The first marker is labeled 208708; the second (consecutive) one 208709                  


Discussion:

Call the first mile marker "m". Then

m + (m+1) = 417417            => combine like terms

2m + 1 = 417417                 => subtract 1 from both sides

2m =  417416                     => divide both sides by 2

m  = 417416/2  = 208708                  

Note: m and (m+1) are consecutive as they immediately follow each other in the set of integers.

Thank you,

MrB

5 0
3 years ago
The tax rate for new york is 7.45%.if nicolas earns 36,000 this year,how much will he pay taxes
Arlecino [84]

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7.45\% of 36000}}{\left( \cfrac{7.45}{100} \right)36000}\implies 2682

4 0
3 years ago
A protective cover for a wireless tablet has a height of 8 inches and base of 7 inches. What is the area of the cover?
RUDIKE [14]
So to find the answer of the area, you have to multiply 7 and 8 which would equal to 56.
6 0
3 years ago
Read 2 more answers
Given the isosceles trapezoid below, find AG.<br> Show all the work
Dmitry [639]

We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

40 - 24 = 16

Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of GT and EF

\frac{16}{2} = 8

Finally, we can use the Pythagorean Theorem to find the length of AG:

AG^{2} + GT^{2} = AT^{2}

AG^{2} + 8^{2} = 10^{2}

AG^{2} + 64 = 100

AG^{2} = 36

AG = 6

8 0
2 years ago
3/8 x 3/8 simplified
enot [183]
The answer to this problem is 9/64.
4 0
3 years ago
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