Answer:
Let the 1st group be of students and 2nd group be of faculty.
n1 = 18
\bar{x}_{1} = 8.4
s1 = 7.3
n2 = 15
\bar{x}_{2} = 4.2
s2 = 3.8
1.
H0: =
HA: >
2.
Equality of variance test:
F = s12/s22
= 53.29/14.44
= 3.69
df-num = n1-1 = 17
df-den = n2-1 = 14
p-value = 0..008 < 0.05 i.e.H0 can be rejected and hence we can say that both populations do not have the same variances.
So, test-statistic will be calculated as follows:
[ Find the solution of this part in the attachment]
3.
df = 26
p-value = 0.0217
4.
E. It confirms the community college results because the p-value is much smaller.
Answer:
2 1/2
Step-by-step explanation:
since it two halves multiplied, it'd be 2 1/2. you can also mulitpy decimals to get ur answer
breainliest pls
Answer:
$39.25.
Step-by-step explanation:
0.09 * 36 = 3.24
3.24 + 36 = 39.25
Answer:
453
Step-by-step explanation:
12×48=576 (number of stickers she has)
576-123=453 (number of stickers she had-number of stickers she had left)