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3 years ago

What is the image of (0,-8) after a reflection over the line y=x

Mathematics

1 answer:

vfiekz [6]3 years ago

8 0

Answer:

(0,8)

Step-by-step explanation:

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-2y + 6 = -12<br><br> Please help me what is Y

patriot [66]

Answer:

y = 9

Step-by-step explanation:

-2y + 6 = -12

-6 -6

-2y = -18

divide both sides by -2

y = 9

Hope this Helps!!!

7 0

3 years ago

Read 2 more answers

Simplify the complex fraction.

lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}$

Step 2: Simplify the denominator

$$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}$

Step 3: Using step 1 and step 2

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}$

Step 4: Using fraction rule:

$$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}$

$$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}$

Cancel the common factor r and t², we get

$$=\frac{64 r^{2} \cdot 9 }{16 \cdot 15 t^2 }$

Cancel the common factors 16 and 3 on both numerator and denominator.

$$=\frac{4 r^{2} \cdot 3 }{ 5 t^2 }$

$$=\frac{12 r^{2} }{ 5 t^2 }$

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2} }{ 5 t^2 }$

The simplified fraction is $\frac{12 r^{2} }{ 5 t^2 }$ .

5 0

3 years ago

Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!

Paladinen [302]

The answers are A and D. Hope this helps!

6 0

3 years ago

Vavilen inflated a huge balloon in 19 minutes. Then he poked a hole in the balloon so that it slowly leaked air out until it was

kaheart [24]

Considering balloon to be an spherical object

Volume of sphere = $\frac{4}{3}\pi r^3$ , where r is the radius of sphere.

After 19 minutes ,If radius of balloon changes from r to R, the Volume changes from V to V'.

V'= $\frac{4}{3}\pi R^3$ ,

As given,rate at which the air leaked out of the balloon (in liters of air per minute) was half of the rate at which Vavilen inflated the balloon.

Also, $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

Now, again the radius changes from R to r.So, Volume changes from V' to Back to V.

Time taken by the balloon to deflate = 38 minutes

But there is no relation between time and volume of Balloon.

So, we can't predict at which rate balloon is deflating or inflating.Apart from the statement given in Question: $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

7 0

4 years ago

Read 2 more answers

Help please!!!!!!!!!!!

Sophie [7]

4.
$\{x|x\leqslant 4\}$

5.
$[-7,\infty)$

6.
$-3\leqslant x < 5$

7 0

4 years ago