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tamaranim1 [39]
3 years ago
15

What percent of 700 is 364

Mathematics
1 answer:
viktelen [127]3 years ago
6 0

Answer:

52%

Step-by-step explanation:

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Find the measure of ∠6 please help! answer and how to do it?
Nana76 [90]

Answer:

56 degrees

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which equation is correct? 2x+38) - 5x +4 A 7x - 41 B 7x + 41 C 36x - 2<br>or just write your own
bija089 [108]

Answer:

-3x+42

Step-by-step explanation:

(2x+38) - 5x +4

2x+38 - 5x +4

2x+38+ - 5x +4

2x+-5x+38+4

-3x+42

5 0
4 years ago
All the students in the six grade either purchase their lunch or brought their lunch from home on Monday 24% of the students pur
juin [17]
Percent of students brought their lunch from home is 100-24= 76%
So, total students are in the six grade is
190 x 100/76 = 250 students
7 0
3 years ago
Through the point (3,1.2) that has an y intercept of 3
topjm [15]

Answer:

y = -0.6x +3

Step-by-step explanation:

equation of the line through point (3, 1.2) and y-interecept of 3

y= mx+b

m is the slope and b is thhe y-intercept

y = mx + 3

between points (3, 1.2) and (0,3) the slope is

m= (y2-y1)/ (x2-x1) = (1.2-3) / (3-0) = -1.8/3 = -0.6

y = -0.6x +3

3 0
3 years ago
Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

5 0
3 years ago
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