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3 years ago

What's the difference of the two polynomials? (9x²+8x)-(2x²+3x)A)7x²+5x

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

<h2>Answer:</h2>

7x²+5x

<h2>Step-by-step explanation:</h2>

(9x²+8x)-(2x²+3x)

We will subtract the like terms. That means that we will subtract $2x^{2}$ from $9x^{2}$ and 3x from 8x.

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2 years ago

Clare and Noah play a game in which they earn the same number of points for each

Korvikt [17]

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Step-by-step explanation:

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Keywords: linear equation, variables

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3 years ago

cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

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2 years ago

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What's the difference of the two polynomials? (9x²+8x)-(2x²+3x)A)7x²+5x​

What's the difference of the two polynomials? (9x²+8x)-(2x²+3x)A)7x²+5x