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Ainat [17]
3 years ago
11

Plzzz help hurry !!!

Mathematics
2 answers:
bekas [8.4K]3 years ago
6 0

Answer and Explanation:

Well since it's just basic graphing, all you have to do is plot the points.  The graph counts by 2, so -7 will be in between -6 and -8.  Then, since the next number is positive, you will need to count up 7 spaces from that point, (so that your final point in up 7 spaces from -7 spaces)  Hope that made sense!  

nexus9112 [7]3 years ago
3 0

Answer:

read below !!

Step-by-step explanation:

go to the left 7 spaces on the x axis... (the horizontal line!). then, go up from that point 7 !!

it should look like the image provided !! i hope this helped :D

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Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.
guapka [62]

\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}

\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill

7 0
2 years ago
Math loversss. PLEASE, HELP.
RideAnS [48]

Answer:

I can say Now it's a positive fuction so the answer choices B and D with the negative 1 is wrong, sense Y is = 0 since the slope goes through 0

Step-by-step explanation:

My guess is Most likely <u><em>A </em></u>Since C The slope is going left to right which is positive

7 0
3 years ago
Please help I'm in need.
Snezhnost [94]
The last one is correct!
8 0
3 years ago
Read 2 more answers
For an angle Θ with the point (12, −5) on its terminating side, what is the value of cosine?
Pachacha [2.7K]
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adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
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plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13

Answer is option . D
5 0
3 years ago
Work out the area of this circle
slavikrds [6]
50.2cm3

Hope this helps!
5 0
3 years ago
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