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olga_2 [115]
4 years ago
9

A variable force of magnitude F(x) moves a body of mass m along the x-axis from x1 to x2. The net work done by the force in movi

ng the body from x1 to x2 is where v1 and v2 are the body's velocities at x1 and x2. Knowing that the work done by the force equals the change in the body's kinetic energy, solve the problem.
Mathematics
1 answer:
kicyunya [14]4 years ago
3 0

Answer:

w=\frac{1}{2}m(v^2_2-v^2_1)

Step-by-step explanation:

We are given that a variable force of magnitude F(x) moves a body along the x- axis from x_1 to x_2.

The net work done by the force in moving the body from x_1 to x_2 .

v_1=Velocity of the body at x_1

v_2=Velocity of the body at x_2

We know that

Work done=Final kinetic energy-Initial kinetic energy

w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1

K.E=\frac{1}{2}mv^2

Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)

Hence, the net work done by the force is given by

w=\frac{1}{2}m(v^2_2-v^2_1)

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Based on the above scenario, the sales director conducted  an <u>experiment</u>.

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