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zimovet [89]
4 years ago
8

Calculate the area of this triangle.14 cm18 cm​

Mathematics
1 answer:
Ede4ka [16]4 years ago
5 0

Answer:

99 cm squared

Step-by-step explanation:

A=hb x b /2

hb: 11

b:18

11x18= 198

198/2= 99

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Name the property of real numbers illustrated by the equation.
sammy [17]
Distributive property :))))
4 0
4 years ago
Read 2 more answers
Simplify: 6(2x-3)-(5x+7)
Gelneren [198K]
First I would distribute the left part like so:
12x - 18 - (5x + 7)

Then I would distribute the right side like so: (I'm just distributing a negative sign)
12x - 18 - 5x - 7

Then I combine like terms like so: (12x and -5x)
7x - 18 - 7

Then I would combine the other like terms like so: (-18 and -7)
7x - 25


I hope that helps! Feel free to let me know if you have any questions! :3

- mathwizzard3
5 0
3 years ago
Sixty percent of U.S. adults trust national newspapers to present the news fairly and accurately. You randomly select nine U.S.
Pavel [41]

Answer:

a) 0.251

b) 0.483

c) 0.0994

Step-by-step explanation:

We are given the following information:

We treat adult adults trusting national newspapers to present the news fairly and accurately as a success.

P(Adult trust) = 60% = 0.6

Then the number of adults follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 9

a) exactly five

P(x = 15) = \binom{9}{5}(0.6)^{5}(1-0.6)^{9-5} = 0.2508 \approx 0.251

b) at least six

We have to evaluate

P(x \geq 6) = P(x = 6) + P(x = 7) + P(x=8) + P(x=9) \\= \binom{9}{6}(0.6)^6(1-0.6)^3 + \binom{9}{7}(0.6)^7(1-0.6)^2 + \binom{9}{8}(0.6)^8(1-0.6)^1 +\binom{9}{9}(0.6)^9(1-0.6)^0\\= 0.482609 \approx 0.483

c) less than four

We have to evaluate

P(x < 4) = P(x = 0) + P(x = 1) + P(x=2) + P(x=3) \\= \binom{9}{0}(0.6)^0(1-0.6)^9 + \binom{9}{1}(0.6)^1(1-0.6)^8 + \binom{9}{2}(0.6)^2(1-0.6)^7 +\binom{9}{3}(0.6)^3(1-0.6)^6\\= 0.099352 \approx 0.0994

3 0
3 years ago
What is a number greater than 18. 55 and less than 18. 6
Verdich [7]

It's not hard to find one of those, since there are
an infinite number of them.  Here are a few:

18.55000001
18.56
18.57
18.58
18.59
18.591
18.59100001
18.59100002
18.59100003
18.59100004
18.59100005
18.5910006
18.591007
18.59108
18.5919
18.59191
18.59192
18.59193
.
.
etc.

     
3 0
3 years ago
Read 2 more answers
WHOEVER SOLVES THIS GETS 20PTS!!!!!! PLS HELP NOW
gulaghasi [49]
4 the answer is 4. DUHH
did I get it right
8 0
3 years ago
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