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solong [7]
2 years ago
15

Simplify. (0.4n)(16n)

Mathematics
1 answer:
BigorU [14]2 years ago
4 0
=(0.4n)(16n)
multiply 0.4 & 16 and n & n
=(0.4*16)(n * n)
=6.4n^2

Hope this helps! :)
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Best answer gets brainliest​
Luden [163]
K= -3

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3 0
3 years ago
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

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The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
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3 years ago
Write the first five terms of the sequence. an=n2 +2​
Alla [95]

Answer:

The first five terms of the given sequence

3, 6, 11, 18, 27

Step-by-step explanation:

It is given that,

an=n² +2​

<u>To find the first five terms</u>

a₁ = 1² + 2 = 1 + 2 = 3

a₂ = 2² + 2 = 4 + 2 = 6

a₃ = 3² + 2 = 9 + 2 = 11

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a₅ = 5² + 2 = 25 + 2 = 27

Therefore the first five terms of the given sequence

3, 6, 11, 18, 27

4 0
3 years ago
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