Which of the following terms describes surgery through a small incision in the abdomen?

The power ratio 1.774 is equivalent to how many dB?

kvv77 [185]

Answer:

2.489 dB

Solution:

As per the question:

Power ratio, $\frac{P'}{P} = 1.774$

The Equivalent of this power ratio in decibel or dB is calculated by taking the log of the power ratio as below:

$\frac{P'}{P}_{dB} = 10log_{10}\frac{P'}{P}$

$\frac{P'}{P}_{dB} = 10log_{10}\times 1.774 = 10\times 0.2489 = 2.489 dB$

Thus the value of the power ration in decibel comes out to be 2.489 dB

3 0

3 years ago

To steal credit card information by installing devices on card readers located in ATMs, gas pumps, restaurants, grocery stores,

riadik2000 [5.3K]

Answer:

Skimming

Explanation:

7 0

3 years ago

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⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val

timurjin [86]

Answer:

a) There are approximately 2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b) ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 = 4.824 × 10^9 bytes. Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a) There are approximately 2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b) ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 = 4.824 × 10^9 bytes. Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0

2 years ago

In 4-bit two's complement representation, what is the binary encoding of the number -5?

Katena32 [7]

Answer:

a) 1011

Explanation:

In 4 bit two's complement representation, the first bit is the sign bit.

If the sign bit is 1, the number is negative.

If the sign bit is 0, the number is positive.

What is the magnitude of the sign bit?

In n-bit two's complement representation, the magnitude of the sign bit is:

$2^{n-1}-1$

So, in 4-bit two's complement representation, the magnitude of the sign bit is:

$2^{4-1}-1 = 8$

Since the number is negative, the value of this bit is -8.

The other bits are magnitude bits, positive.

We have that the sum of these bits must be -5, and we already have -8. So what should be the value of these last 3 bits?

First, i am going to solve this equation to find the decimal value of the last three bits.

$-5 = -8 + x$

$x = 3$

So, the last three bits are:

$3_{10} = (011)_{2}$

The binary encoding of the number -5 is:

a) 1011

5 0

3 years ago

Leslie Is doing a sociological study of people who have live remote island. She interviews the people and than she observes them

dimulka [17.4K]

Making guesses, as opposed to the other answers, this is the only one that forges new ideas and doing such will only lead to an illegitimate conclusion/study.

5 0

2 years ago

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