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kirill115 [55]
3 years ago
11

Which of the following terms describes surgery through a small incision in the abdomen?

Computers and Technology
1 answer:
ra1l [238]3 years ago
4 0
Which of the following terms describes surgery through a small incision in the abdomen? Laparoscopy. Laparoscopy is super done by using a fiber-optic instrument that is inserted through the abdomen. When this type of instrument is used, the incision is small and there are smaller cuts made to the person being operated on. 
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CPU BENCHMARKS are measurements used to compare performance between processors
Troyanec [42]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

CPU benchmarks are used to picking the best CPU. If you want to pick the best CPU for the kind of work you do is easier if you research some performance benchmarks.

As you know, CPU benchmarks are measurements used to compare performance between processors. These benchmarks are the measure to know the performance of CPU.

These CPU Benchmarks are generated by running software programs specifically designed to push the limits of CPU performance.

3 0
3 years ago
The expression that is tested by a switch statement must have a(n) __________ value.
Hitman42 [59]

The answer is relational.

6 0
3 years ago
Software that translates the sound of human voice into text is called:________.
S_A_V [24]

Answer:

C) speech recognition software.

Explanation:

Software that translates the sound of human voice into text is called a speech recognition software.

In Computer science, a speech recognition software is a voice technology application or program which enables the conversion of human voice such as spoken language to computer commands such as text through the use of speech recognition algorithms.

Some examples of speech recognition software are HTK, Kaldi, Voice navigator, Julius etc.

6 0
3 years ago
Does any body like animal jam
cricket20 [7]

Answer:

Never used it so I do not know.

Explanation:

To be honest i thought you meant like animal jelly at first

7 0
3 years ago
Read 2 more answers
Edhesive 6.8 lesson practice answers
FromTheMoon [43]

Answer:

1.) 25 ; 15 ; 15

2.) 50 ; 15 ; 50

Explanation:

In the first function written :

The variable val was initially decaled or assigned a value of 25 and that was what was printed first.

However, after the example function was written, the val variable was finally assiagned a value of 15 within the function. However, it was also declared that the global variable takes uonthe val value. Hence, the val variable initially assigned a value, of 25 changes to 15 globally.

For the second code :

From the top:

Val was assigned a value of 50 ;

Hence,

print(val) gives an output of 50

Within the function definition which prints the value of val that is assigned a value of 25 within the function.

Since tbe global variable isnt reset.

Printing Val again outputs 50;since ito is outside the function.

6 0
3 years ago
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