Question

What volume does 4.24g of argon gas occupy at 58.2 degrees celcuis and 1528torr

Answer 1

The volume occupied by the argon gas is, 1.44 L

Explanation :

To calculate the volume of argon gas we are using ideal gas equation:

$PV=nRT\\\\PV=\frac{w}{M}RT$

where,

P = pressure of argon gas = 1528 torr = 2.010 atm

Conversion used : (1 atm = 760 torr)

V = volume of argon gas = ?

T = temperature of argon gas = $58.2^oC=273+58.2=331.2K$

R = gas constant = 0.0821 L.atm/mole.K

w = mass of argon gas = 4.24 g

M = molar mass of argon gas = 39.95 g/mole

Now put all the given values in the ideal gas equation, we get:

$(2.010atm)\times V=\frac{4.24g}{39.95g/mole}\times (0.0821L.atm/mole.K)\times (331.2K)$

$V=\frac{4.24g}{39.95g/mole}\times \frac{(0.0821L.atm/mole.K)\times (331.2K)}{2.010atm}$

$V=1.44L$

Therefore, the volume of occupied by argon gas is 1.44 L