Question

Write the series -25-22-19 +....for 14 terms using summation notation.

Answer 1

Answer:

$\sum_{n=1}^{14}(3n-28)$

Step-by-step explanation:

The given series is

$-25-22-19+...$

The the first term of the sequence is;

$a_1=-25$

The constant difference is;

$d=-22--25$

$d=3$

The nth term of the series is

$a_n=a_1+d(n-1)$

$a_n=-25+3(n-1)$

$a_n=-25+3n-3$

$a_n=3n-28$

Using the summation notation, we can write the series as;

$\sum_{n=1}^{14}(3n-28)$