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3 years ago

10

A marching band stands in a triangle formation. The drum major stands at A, one of the vertices of the triangle. The whole forma

tion marches 3 units left and 5 units up. They then march 2 units left and 2 units up. After the movement, what coordinates will the drum major be standing on?

1 answer:

erastova [34]3 years ago

6 1

Answer: it's (11,11)

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A team of scientist surveying a forest found that there were four oak trees for every 10 pine trees. If they counted 24 more pin

Ipatiy [6.2K]

Answer:

There are 16 Oak tree in the forest.

Step-by-step explanation:

Given: There are 4 Oak tree on every 10 pine trees.

There are total 24 more pine tree than Oak tree.

Using the ratio of trees to find the number of trees.

Lets assume there are total number of Oak tree be "x".

∴ Total number of Pine trees will be $"x+24"$

We know the ratio of Oak to Pine tree is 4:10 or $\frac{4}{10}$

⇒ $\frac{x}{x+24} = \frac{4}{10}$

Multiplying both side by $x+24$

⇒ $x= \frac{4(x+24)}{10}$

Using distributive property of multiplication, distributing 4 with x and 24.

⇒ $x= \frac{4x+96}{10}$

Multiplying both side by 10

⇒ $10x= 4x+96$

subtracting both side by 4x

⇒ $6x= 96$

dividing both side by 6

⇒ $x= \frac{96}{6}$

∴ $x= 16$

Hence, There are 16 Oak trees in the forest.

5 0

3 years ago

Write and equation of the line that passes through the pair of points (4,6) and (-1,1)

bazaltina [42]

Answer:

y = x + 2

Step-by-step explanation:

Step 1: Find the slope

$m=\frac{y2-y1}{x2-x1} = \frac{6-1}{4-(-1)}=\frac{6}{6} =1$

Step 2: Substitute the slope and a point in to find y intercept

(6)=(1)(4)+b

6 = 4 + b

b = 2

Step 3: Substitute all the information in

y = x + 2

Therefore the equation for a line that passes through (4,6) and (-1,1) is y = x + 2

7 0

2 years ago

Read 2 more answers

Simplified or solved for x ????

Leya [2.2K]

$\dfrac{16 \pm \sqrt{-32} }{2}$

$\dfrac{16 \pm \sqrt{-16 \times 2} }{2}$

$\dfrac{16 \pm 4i\sqrt{2} }{2}$

$8 \pm 2i \sqrt{2}$

5 0

2 years ago

The Northeastern United States is getting another snowstorm! Sean, a fifth grade student, decides he will measure how many inche

Wewaii [24]

7 and 3/8 would be the correct answer

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2 years ago

Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me

Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean $\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$\mu = 11.5, \sigma = 4$

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have $n = 50, s = \frac{4}{\sqrt{50}} = 0.5657$

This probability is 1 subtracted by the pvalue of Z when X = 12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{12 - 11.5}{0.5657}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so $mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28$

This probability is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 575}{28.28}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c. What is the approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers.

This is X when Z has a pvalue of 0.95. So it is X when Z = 1.645.

$Z = \frac{X - \mu}{s}$

$1.645 = \frac{X- 575}{28.28}$

$X - 575 = 28.28*1.645$

$X = 621.5$

The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

5 0

2 years ago