Answer:
x = 0
, y = 7/6
Step-by-step explanation:
Solve the following system:
{18 y - 12 x = 21
6 x - 9 = -9
In the second equation, look to solve for x:
{18 y - 12 x = 21
6 x - 9 = -9
Add 9 to both sides:
{18 y - 12 x = 21
6 x = 0
Divide both sides by 6:
{18 y - 12 x = 21
x = 0
Substitute x = 0 into the first equation:
{18 y = 21
x = 0
In the first equation, look to solve for y:
{18 y = 21
x = 0
Divide both sides by 18:
{y = 7/6
x = 0
Collect results in alphabetical order:
Answer: {x = 0
, y = 7/6
Answer: graph E.
A geometric sequence can be written as:

where:
a₁ = first term = 4
r = ratio = 0.5
Substituting the numbers, we have:

or else

This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).
In order to choose between graph B and E, let's evaluate the function in two different points:


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
step 1
Find the measure of length side FG
In the right triangle EFG
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values


step 2
Find the measure of length side EF
In the right triangle EFG
we know that
----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values


step 3
Find the measure of angle G
we know that
---> by complementary angles in a right triangle

Answer:
oa
Step-by-step explanation: