Answer: Tristan can pick them out in 6 different ways
Step-by-step explanation: In the waiting room the four magazines all have an equal chance of being picked first and then others would be picked subsequently. If we are to pick magazine A first of all, then the others would be picked as B, C and D, or C, B and D, or D, B and C, and so on.
However, rather than spend so much time counting the different ways we can apply the mathematical method of permutation. Since choosing the first one means we can’t choose it again but others have to be chosen, and all four magazines each has an equal chance of being chosen first, then the number of all possible permutations is given as 4! (four factorial).
The question requires us to chose three out of the four magazines, so we shall apply 3!.
3! = 3 x 2 x 1
3! = 6
Therefore, there are 6 different ways to pick three out of the four magazines
Answer:
18/5
Step-by-step explanation:
36/10
First find a number that goes into both the two numbers.
...2 can go into both of them...
36 / 10
(÷2) (÷2)
18 / 5
Now we have to see if any other number goes in to these new numbers...
There are no numbers that goes into both...
Hope this helped! <3
Answer:
6
Step-by-step explanation:
-2, -3, -4.
an integer is a number that isn't a fraction. so literally any natural number like 1, 0, or -1. all integers.
