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artcher [175]
3 years ago
15

Help me please what number represented by the shaded position

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0
Count the total number of squares.

There are 10 by 10 of them or:

\sf 10\cdot 10=100

So there are a total of 100 squares, now count the shaded squares.

\sf 4\cdot 4=16

There are 16 shaded squares out of 100, this is a fraction:

\sf\dfrac{16}{100}=\boxed{\sf 0.16}

So your answer is C.
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Help? I can't seem to understand arithmegic sequence.
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A sequence \{a_n\} is arithmetic if the difference between consecutive terms is some fixed number, regardless of which pair of consecutive terms you pick out of the sequence.

For example, the following sequences are arithmetic:

1, 2, 3, 4, 5, 6, ... (difference = 1)

-25, -20, -15, -10, -5, ... (difference = 5)

2. Carla's sequence is not arithmetic, because the differences between consecutive terms are all different:

13 - 11 = 2

17 - 13 = 4

25 - 17 = 8

She can adjust the sequence by changing the last two numbers to 15 and 17, since this makes the difference fixed:

13 - 11 = 2

15 - 13 = 2

17 - 15 = 2

and so on.

3. The sequence

45, 48, 51, 54, ...

is arithmetic with difference 3 between terms. Recursively, we can write the nth term, a_n, in terms of the previous, (n-1)th term, a_{n-1}:

a_n=a_{n-1}+3

By this definition, we can just as easily write the (n-1)th term in terms of the (n-2)th term:

a_{n-1}=a_{n-2}+3

Then, substituting this into the previous equation, we have

a_n=(a_{n-2}+3)+3=a_{n-2}+2\cdot3

We can continue this process to write a_n in terms of a_1:

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a_{n-3}=a_{n-4}+3\implies a_n=a_{n-4}+4\cdot3

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a_n=a_1+(n-1)\cdot3

The first term in this sequence is a_1=45, so we have

a. a_n=45+3(n-1)=42+3n

where n=1,2,3,\ldots.

b. You can fill in the blanks by just adding 3 to the previous term:

45, 48, 51, 54, <u>57</u>, 60, <u>63</u>, 66, 69, ...

Then, using the formula found in (a), the 15th term of the sequence is

a_{15}=42+3\cdot15=87

4 0
2 years ago
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