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julsineya [31]
3 years ago
11

Helppp please use previous question

Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0
I will answer if u post the ?s in a coment
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What is the equation of this line?<br><br>A: y=-3/2x<br>B: y=2/3x<br>C: y=-2/3x <br>D: y=3/2x​
creativ13 [48]

Answer:

b) y = 2/3x

Step-by-step explanation:

Slope (m) formula: \frac{y_2-y_1}{x_2-x_1}

I will be using (3,2) and (-3,-2) to find the slope:

m=\frac{-2-2}{-3-3}\\m=\frac{-4}{-6} \\m = \frac{2}{3}

y = mx + b\\y = \frac{2}{3}x+b

(3,2)

y = \frac{2}{3}x+b\\\\2 = \frac{2}{3}(3)+b\\\\2 = 2+b\\-2  -2\\\\0=b

y=mx+b\\\\y = \frac{2}{3}x+0\\\\y = \frac{2}{3}x

Hope this helps!

8 0
2 years ago
What is the area of a right triangle with a base of 25 centimeters and a height of 13 centimeters?
sdas [7]

Answer:

<h3>162.5 cm²</h3><h3>Step-by-step explanation:</h3>

Area of a triangle = (BH)/2

Base= 25

Height=13

(25×13)/2= 162.5 cm²

6 0
3 years ago
The mass of Earth is 5.97 &gt;&lt; 1024 kilograms. The mass of the Moon is 7.34 x 1022 kilograms. What is the combined mass of E
LuckyWell [14K]

Answer:

7.34x10^22 kg can also be written as 0.0734 * 10^24 kg

Since both numbers are * 10^24, you can just add 5.97 + 0.0734 = 6.043. Then you have to add the * 10^24 giving you 6.043 * 10^24 kg

The ratio of Earth / moon is 5.97x10^24 / 7.34x10^22 = 81. The mass of the Earth is 81 times the mass of the moon.

Step-by-step explanation: give me brainliest please :)

6 0
3 years ago
Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean \mu, standard deviation \sigma.

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

8 0
3 years ago
Which is the equation of OB?
GrogVix [38]
The answer is b I hope this helps
6 0
3 years ago
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