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Brums [2.3K]
3 years ago
10

A hundred percent turned into a decimal

Mathematics
2 answers:
faltersainse [42]3 years ago
4 0
100%=1.0 hope this helps
Anton [14]3 years ago
3 0
100% is just 1 or 1.
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What graph best represents y=2^x + 1
Citrus2011 [14]

Answer:

The graph that best represents the given equation in the attached figure

Step-by-step explanation:

we have

y=2^x+1

Find the y-intercept

Remember that the y-intercept is the value of y when the value of x is equal to zero

For x=0

substitute

y=2^0+1=2

The y-intercept is the point (0,2)

The given function is increasing, because the y-value increases as the x-value increases. The function tends to go up as it goes along

therefore

The graph that best represents the given equation in the attached figure

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3 years ago
What is the equation of the asymptote? f (x) = 3^x-5+1<br> y=?
Natasha_Volkova [10]

The equation of the asymptote is y=1

Explanation:

The given equation is f(x)=3^{x-5}+1

We need to determine the horizontal asymptote of the equation.

The given equation is of the exponential function of the form f(x)=c \cdot n^{a x+b}+k and has a horizontal asymptote y=k

Hence, from the above equation, the value of k is 1.

Therefore, we have,

k=1

Thus, the horizontal asymptote is y=1

Therefore, the asymptote of the equation is y=1

4 0
3 years ago
Which of the following is the equation of a line that passed though the points (2,5) and (4,3)
STatiana [176]

The correct answer is C as it has the same line of equation. We can make this clear by verifying that these two points make the same equation or not. So as we can see if we calculate the gradient using the formula y2 - y1 / x2 - x1.

As we now know that the gradient is -1. We can simply put any one point in the equation y - y1 = m(x - x1) to get the line of equation. WHen we calculate the line of equation it come out to be y = -x + 7

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4 years ago
2. Find the area of the regular polygon.
frozen [14]

Answer:

a. 80 units

b. 482.843 units²

Step-by-step explanation:

<em>First</em><em> </em><em>things</em><em> </em><em>first</em><em>,</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>solve</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>octagon</em><em>. </em><em>We</em><em> </em><em>can</em><em> </em><em>do</em><em> </em><em>so</em><em> </em><em>by</em><em> </em><em>using</em><em> </em><em><u>Pythagorean</u></em><em><u> </u></em><em><u>Theorem</u></em><em><u>:</u></em><em> </em><em>a</em><em>²</em><em> </em><em>+</em><em> </em><em>b</em><em>²</em><em> </em><em>=</em><em> </em><em>c</em><em>²</em><em> </em><em>where</em><em> </em><em>c</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em><u>hypotenuse</u></em><em> </em><em>and</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>two</em><em> </em><em>sides</em><em>. </em>

12² + b² = 13²

144 + b² = 169

b² = 25

b = 5

<em>Now</em><em> </em><em>that</em><em> </em><em>we</em><em> </em><em>know</em><em> </em><em>half</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>octagon</em><em> </em><em>is</em><em> </em><em>5</em><em>,</em><em> </em><em>we</em><em> </em><em>know</em><em> </em><em>that</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>octagon</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>.</em><em> </em>

<em>a</em><em>.</em><em> </em><em>To</em><em> </em><em>find</em><em> </em><em>perimeter</em><em> </em><em>we</em><em> </em><em>just</em><em> </em><em>add</em><em> </em><em>every</em><em> </em><em>side</em><em> </em><em>together</em><em> </em><em>(</em><em>or</em><em> </em><em>since</em><em> </em><em>every</em><em> </em><em>side</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>size</em><em>,</em><em> </em><em>we</em><em> </em><em>multiply</em><em> </em><em>by</em><em> </em><em>8</em><em>)</em>

10 × 8 = 80

<em>b</em><em>.</em> <em>The</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>the</em><em> </em><em>area</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>octagon</em><em> </em><em>is</em><em> </em><em>2</em><em>(</em><em>1</em><em> </em><em>+</em><em> </em><em>radical</em><em> </em><em>2</em><em>)</em><em>a</em><em>²</em><em> </em><em>where</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>length</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>side</em><em>.</em><em> </em><em>By</em><em> </em><em>plugging</em><em> </em><em>in</em><em> </em><em>to</em><em> </em><em>a</em><em> </em><em>calculator</em><em> </em><em>we</em><em> </em><em>get</em><em>:</em>

2(1 + radical 2)(10)² = 482.843

3 0
3 years ago
Kristin drinks 0.5 liters of orange juice with breakfast each day for 15 days. How many milliliters of orange juice does Kristin
evablogger [386]

Answer:

she drank 7500 milliliters of juice

Step-by-step explanation:

In this question, we are asked to calculate the amount of juice in milliliters consumed by Kristin.

From the question, she drank 0.5 liters per day for 15 days. This means that the total amount she drank for the 15 days will be 0.5 * 15 = 7.5 liters

what we now need to do is to calculate the equivalent of this in milliliters.

To get this, we need to multiply the volume in liters by 1000. This is simply because 1000 milliliters make 1 liter

so that will be 7.5 * 1000 = 7500 milliliters of juice

3 0
3 years ago
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