
To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
I think form reading this your going to need to add or divded i need more informtaion to understand your question
Answer:
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 158.9
Standard Deviation, σ = 90.4
We are given that the distribution is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.39
Calculation the value from standard normal z table, we have,

133.68 separates the bottom 39% means from the top 61% means.
Answer:
C
Step-by-step explanation:
We want the equation of the line that passes through (3, 6) and is perpendicular to:

First, convert the second equation into slope-intercept form:

So, we can see that the slope of the line is 3/4.
The slopes of perpendicular lines are negative reciprocals of each other.
Therefore, the slope of the new line is -4/3.
It passes through the point (3, 6).
We can use the point-slope form:

Substitute:

Distribute:

Therefore:

The answer is C.