Question

Help with this math question

Answer 1

Answer:

$-\frac{13\sqrt{x} }{x}$

Step-by-step explanation:

We have been given the following expression;

-13/√x

In order to rationalize the denominator, we multiply the numerator and the denominator by √x;

$-\frac{13}{\sqrt{x}}=-\frac{13\sqrt{x} }{\sqrt{x}\sqrt{x}}\\ \\-\frac{13\sqrt{x} }{\sqrt{x^{2} } }\\\\-\frac{13\sqrt{x} }{x}$