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Ray Of Light [21]
3 years ago
10

What is the surface area, in centimeters, of a cube with a side length, s, of cm?

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0
Area is 6s^2 and that’s one side: a cube has 6 sides so the surface area is 6(6s^2) = 36s^2 cm
oee [108]3 years ago
3 0

Answer:

216cm

Step-by-step explanation:

i think that's right

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Simplify the following expression:
Phantasy [73]
\frac{4}{ \frac{1}{4} - \frac{5}{2} }

To begin, we can simplify the expression's denominator by finding a common denominator between the denominators of the fractions in the denominator.  To make them compatible, we can convert \frac{5}{2} into \frac{10}{4}:

\frac{4}{ \frac{1}{4} - \frac{5}{2}( \frac{2}{2}) } = \frac{4}{ \frac{1}{4} - \frac{10}{4} }

Next, we can simplify:

\frac{4}{ \frac{1}{4} - \frac{10}{4} } = \frac{4}{ -\frac{9}{4}}

Finally, to cancel the denominator within the denominator, we can multiply the whole expression by \frac{4}{4}, or 1:

\frac{4}{ -\frac{9}{4}}* \frac{4}{4} =  -\frac{16}{9}

The expression simplifies to -\frac{16}{9}, or -1 \frac{7}{9} as a mixed number.
6 0
3 years ago
Read 2 more answers
Please help!!!!!! ASAP!!!
Kitty [74]

Answer:

B. po ang answer sa palagay ko lang po

6 0
2 years ago
Give the equation of the line with a slope of -7/2<br> and a y-intercept of - 6
antoniya [11.8K]

Answer:

y =  \frac{ - 7}{2}  - 6

3 0
3 years ago
The geometric sequence shown can be represented by the function y = 5n, where the domain of the function is
alukav5142 [94]
The answer is all real numbers
3 0
3 years ago
Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

4 0
2 years ago
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