All categories

2 years ago

What is the surface area, in centimeters, of a cube with a side length, s, of cm?

Mathematics

2 answers:

alukav5142 [94]2 years ago

5 0

Area is 6s^2 and that’s one side: a cube has 6 sides so the surface area is 6(6s^2) = 36s^2 cm

oee [108]2 years ago

3 0

Answer:

216cm

Step-by-step explanation:

i think that's right

You might be interested in

Carrie has a planter box with an area of 4/5 of a square meter. She wants to plant 10 snap pea seeds each with an equal amount o

Goshia [24]

For this case, what we must do is divide the total area between the number of seeds.
We have then:
A = (4/5) / (10)
Rewriting we have:
A = (4/50)
Simplifying the expression we have:
A = (2/25) of a square meter.
Answer:
she will give to school snap pea plant an area of:
A = (2/25) of a square meter.
option 2

3 0

3 years ago

Read 2 more answers

What would be the best method to use in order to solve the following quadratic equation? x²+14x+13=0

34kurt

2.; it’s the easiest, fastest, and simplest way to get to your factors

4 0

3 years ago

Read 2 more answers

Water coming out from a fountain is modeled by the function f(x) = -x2 + 6x + 6 where f(x) represents the height, in feet, of th

Firdavs [7]

F(x) = -x^2 + 6x + 6

where f(x) represents the height, in feet, of the water from the fountain at different times x, in seconds

rate of change of a distance is speed
at x=5, distance = 11
at x=2, distance = 14
so average rate of change = (14-11)/(5-2) = 1
so ans is D

3 0

3 years ago

Read 2 more answers

Simplify the expression.

Nimfa-mama [501]

The answer is C.15c+72

5 0

2 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago