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Murrr4er [49]
3 years ago
7

Put the following in slope intercept form 4x - 3y = 15

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0

slope intercept form: y = mx + b

Note the equal sign. what you do to one side, you do to the other. First, subtract 4x from both sides

4x - 3y = 15

4x (-4x) - 3y = 15 (-4x)

-3y = -4x + 15

Next, divide -3 from both sides to isolate the y.

(-3y)/-3 = (-4x + 15)/-3

y = (4/3)x - 5

y = (4/3)x - 5 is your answer

hope this helps

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A bag of lawn fertilizer covers 289 square feet

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Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
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a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

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The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

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