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blagie [28]
3 years ago
9

Determine 2 coterminal angles in radians for 7pi/2

Mathematics
1 answer:
bija089 [108]3 years ago
8 0
Check the picture below.

notice, that one go-around is 2π, or namely 4π/2, and if we go 3π/2 more over, we'd end up at at 4π/2 + 3π/2 or 7π/2.

a couple of coterminal angles will be those in blue, one angle in the first go-around, and another one by simply going around one more time by 4π/2 extra, 7π/2 + 4π/2 is just that one there.

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Answer:

(u/v)(x)=-x^{3}+x^{2}-1

Step-by-step explanation:

You have the following functions:

u(x)=x^{5}-x^{4}+x^{2}\\v(x)=-x^{2}

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(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}

Simplify it. Therefore, you obtain:

(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}\\\\(u/v)(x)=-x^{3}+x^{2}-1

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