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SSSSS [86.1K]
3 years ago
12

If a rabbit can move 2 1/4 miles every hour, then how many hours would it take for the rabbit to go 9 miles

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0
It would take 4 hours to go 9 miles.
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3 12 fraction minus 8 12
Alexus [3.1K]
If you are saying:
(3/12) - (8/12)
Then since their denominators are the same we can subtract the numerators to get our answers.

3 - 8 = -5

Following the rule of adding and subtracting fractions, the denominators will not change unless they are different.

So: (3/12) - (8/12) = -5/12
6 0
3 years ago
F(x)=4x+5whsts the value of. F(-3). Is
MArishka [77]
Figure out the value
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Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet
Irina18 [472]

The distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}

Now, we shall solve the problem using the law of sines,

\frac{\sin A}{a}=\frac{\sin C}{c}

Substituting the values, we have,

\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}

\frac{0.9903}{a}=\frac{0.3420}{140}

Simplifying, we get,

a=\frac{0.9903 \times 140}{0.3420}

a=405.4

Thus, the distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

4 0
3 years ago
Given EG = 16 and FH = 12, what is the length of one side
pav-90 [236]
8 is the answer cuz if you dive and all that
6 0
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An architect measures a beam to be 96.55 centimeters long, with an accuracy of plus or minus 0.02 centimeter. Which equation can
olga2289 [7]

Answer:

|96.55−0.02|= x

|96.55+0.02|=x

Step-by-step explanation:

Given that:

Measured length of beam = 96.55 cm

Measurement accuracy = plus or minus (± 0.02cm)

Limits of actual length of the beam:

Let limit of actual length = x

Lower limit :

|measured length - accuracy| = x

|96.55 - 0.02| = x

96.53) x

Upper limit :

|measured length + accuracy| = x

|96.55 + 0.02| = x

96.57 = x

3 0
3 years ago
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