Answer:
2H₂ + O₂       →     2H₂O
Explanation:
Chemical equation:
H₂ + O₂       →     H₂O
Balance chemical equation:
2H₂ + O₂       →     2H₂O
Step 1:
H₂ + O₂       →     H₂O
Left hand side                     Right hand side
H = 2                                    H = 2
O = 2                                    O = 1
Step 2:
H₂ + O₂       →     2H₂O
Left hand side                     Right hand side
H = 2                                    H = 4
O = 2                                    O = 2
Step 3:
2H₂ + O₂       →     2H₂O
Left hand side                     Right hand side
H = 4                                    H = 4
O = 2                                    O = 2
 
        
             
        
        
        
Answer:
See the answer below , please.
Explanation:
In a decomposition reaction, a certain compound is "broken" to give two or more different products.
An example for compound AB, giving as products A and B:
AB -> A + B
In the case of water:
2H20 -> 2H2 + 02,  water decomposes giving Hydrogen and Oxygen
 
        
                    
             
        
        
        
Answer:
B is the answer
Explanation:
Because it a molecular mass of one
 
        
             
        
        
        
Answer:
because plants have energy in them from the sun and 
 
        
                    
             
        
        
        
Answer:
a) 1.71 × 10⁻³ M
b) 8.00 × 10⁻⁵ M
Explanation:
In order to calculate the solubility (S) of Pb(SCN)₂ we will use an ICE chart. We identify 3 stages (Initial, Change, Equilibrium) and complete each row with the concentration or change in the concentration.
        Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)
I                                 0                   0
C                               +S               +2S
E                                 S                  2S
The solubility product (Ksp) is:
Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (2S)² = 4S³
S = 1.71 × 10⁻³ M
<em>b) Calculate the molar solubility of lead thiocyanate in 0.500 M KSCN.</em>
KSCN is a strong electrolyte that dissociates to give 0.500 M K⁺ and 0.500M SCN⁻.
        Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)
I                                 0                 0.500
C                               +S                +2S
E                                 S                0.500 + 2S
Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (0.500 + 2S)² 
In the term (0.500 + 2S)², 2S is negligible.
Ksp = 2.00 × 10⁻⁵ = S . (0.500)²
S = 8.00 × 10⁻⁵ M