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daser333 [38]
3 years ago
9

If I have one mole of sulfur, how many atoms would that be?

Chemistry
1 answer:
krok68 [10]3 years ago
7 0

Answer:

Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1

Explanation:

because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.

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What is the purpose of the uninoculated control tubes used in the oxidation fermentation test?
Black_prince [1.1K]
The purpose of the uninoculated control tubes used in this test is that two uninoculated control tubes are needed to show the results of the medium in both aerobic and anaerobic environments. It is used to show it is sterile and also as a color comparison, used also to show that the medium remains green under both conditions. 
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3 years ago
What does the nucleus of an atom do to its own electrons? To the electrons of a nearby atom?
Margaret [11]
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Due the positive charge of the nucleus of an atom, an atom always want to attract its electrons and keep them near it however it weakly attracts the other electrons of a nearby atom.
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3 years ago
The development of new technology requires the evaluation of the overall benefit to cost ratio of the new technology.
avanturin [10]

Answer:

B and C Reduce Emissions and Least fuel economy

Explanation:

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6 0
3 years ago
50 ml of 0.2 M acetic acid is shaken with 10 g activated charcoal. The concentration of acetic acid is reduced to 0.5 times the
Olegator [25]

Answer:

0.03 g_{acid}/g_{charcoal}

Explanation:

The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.

So, we need to calculate the mass of the acetic acid as follows:

m = n*M = C*V*M

Where:

n: is the number of moles = C*V

M: is the molecular mass =  60.052 g/mol

C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L

V: is the volume = 50 ml = 0.050 L

m_{acid} = C*V*M = 0.10 mol/L*0.050 L*60.052 g/mol = 0.30 g

Now, the amount of solute adsorbed per gram of the adsorbent is:

\frac{m_{acid}}{m_{charcoal}} = \frac{0.30 g}{10 g} = 0.03 g_{acid}/g_{charcoal}

Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.

I hope it helps you!

3 0
2 years ago
What is the mass of 6.02 × 1023 molecules of Fe2O3?
LenKa [72]

Answer: 160 g Fe2O3

Explanation: solution attached.

First convert molecules to moles using Avogadro's number then convert to mass using the relationship between moles and molar mass of Fe2O3

4 0
3 years ago
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