Question

A mixture of gaseous sulfur dioxide and oxygen are added to a reaction vessel and heated to 1000 K where they react to form SO3 (g). If the vessel contained 0.669 atm SO2 (g), 0.395 atm O2 (g) and 0.0851 atom SO3 (g) after the system has reached equilibrium, what is the equilibrium constant, Kp, for the reaction

Answer 1

Answer:

$Kp = 0.0410$

Explanation:

The reaction of gaseous sulfur dioxide and oxygen to form SO3 (g) is:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kp is defined as the ratio of pressure of products and pressure of reactants:

$Kp = \frac{P_{SO_3}^2}{P_{SO_2}^2P_{O_2}}$

$Kp = \frac{0.0851atm^2}{0.669atm^2*0.395atm}$

$Kp = 0.0410$

I hope it helps!