Solution :
Give that a shark can chase prey about 30 miles per hour.
1 hour = 60 minute
by using unitary method, we will convert miles per hour into miles per minute
in 60 minutes the shark can chase the prey 30 miles
In 1 minute the shark can chase 
Hence the shark can chase the prey about 0.5 miles per minute.
Answer:
The correct answer is - 12.
Step-by-step explanation:
Given:
Total number of people = y = 39x+50
Total amount spent y = 518
Solution:
The equation for the number of people who attended the dinner
y = 39x+50
The cost of dinner is equally divided by number of people =
then, 518 = y
placing value, 518 = 39x+50
x = (518-50)/39
= 468/39
= 12
Then number of people attended the dinner = 12
X + 3 = 0
2x - 1 = 0
It would be D.
So the formula is
7*(1/3+1/5) = x
First find the common denominator of the fractions. In this case the common denominator of 3 and 5 is 15 so we must convert them to 15ths. To do that we divide 15 by the denominator and take that answer and multiply the numerator by it.
So for 1/3 we take 15/3(denominator) = 5 and multiply the numerator (1) by it
5 * 1 = 5 so 1/3 converts to 5/15
Do the same for 1/5 we take 15/5 = 3 and multiply the numerator (4) by it
3*4 = 12 so 4/5 converts to 12/15
Now we add 5/15 and 12/15 = 17/15 so we have our formula now to
7*17/15
We make seven a fraction 7/1 and multiply across 7*17 = 119 and 15 * 1 = 15
We have 119/15 which when we divide and get 7 14/15 as your answer
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
