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Luden [163]
3 years ago
12

How would you sole this equation if you were solving for x ? 6x-2x+7=23

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0
Put the x on one side of the equation (divide x from the 6 and 2)
Eddi Din [679]3 years ago
3 0
Combine like terms first:

4x+7=23
Subtract seven from both sides:4x=16
Divide both sides by 4
x=4

Plug 4 into the original equation to check work:6(4)-2(4)+7=23
24-8+7=23
16+7=23
23=23
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Determine whether the relation is a function (-4,12), (1,6), (4, -2), (7-8), (10,-14)
erastovalidia [21]

No,it is not a function.

8 0
3 years ago
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To earn extra money before school, Julia shovels snow from her neighbors' driveways for $6 each. This morning, Julia shoveled 27
Brrunno [24]
27 times 6
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I think that’s right
4 0
2 years ago
Find the minimum or maximum value of the function g(x)= -(x-2)^2-3
Nady [450]
Neato

assuming you mean
g(x)=-1(x-2)^2-3
remember
in form
f(x)=a(x-h)^2+k
a is leading coficient
(h,k) is vertex
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if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max

given
g(x)=-1(x-2)^2-3
a is negative
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3 0
3 years ago
Consider the following.
8_murik_8 [283]

Answer:

Step-by-step explanation:

You've typed the equation incorrectly. 3^5x-1 = 3⁵x-1.

It needs to be typed as 3^(5x-1) = 7.

3 0
3 years ago
What is the derivative of this function?
Alex17521 [72]
\bf y=\sqrt{x}-\left( \frac{1}{2} \right)^x\implies y=x^{\frac{1}{2}}-\left( \frac{1}{2} \right)^x\implies \cfrac{dy}{dx}=\frac{1}{2}x^{\frac{1}{2}-1}-\left( \frac{1}{2} \right)^xln\left( \frac{1}{2} \right)
\\\\\\
\cfrac{dy}{dx}=\frac{1}{2}x^{-\frac{1}{2}}-\left( \frac{1}{2} \right)^xln\left( \frac{1}{2} \right)\implies 
\cfrac{dy}{dx}=\cfrac{1}{2\sqrt{x}}-\left( \frac{1}{2} \right)^xln\left( \frac{1}{2} \right)
6 0
3 years ago
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