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3 years ago

Someone help with this ?

Mathematics

1 answer:

siniylev [52]3 years ago

8 0

Answer:

mela chupas perra hgjygu

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Please Help!: 36x = $45.00

artcher [175]

45.00/ 36
move the decimal. do the same to the 36.
4500/ 3600
1.25

7 0

3 years ago

Solve for x Ax + B = C

Ahat [919]

Answer:

(C - B)/A = x

Step-by-step explanation:

Ax + B = C

-B -B

Ax = C - B

Divide both sides by A

x = (C - B)/A

(C - B)/A = x

4 0

3 years ago

Choose the equation that satisfies the data in the table

LenKa [72]

$\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}$

See this attachment

option D is correct

5 0

3 years ago

Midpoint Formula:

Sedaia [141]

The coordinates of the midpoint of the segment joining the two points (0, 2) and (6, 4) is (3, 3)

<h3>Solution:</h3>

Given that two points are (0, 2) and (6, 4)

To find: coordinates of the midpoint of the segment joining the two points

The midpoint of line joining two points is given as:

For a line containing two points $(x_1, y_1)$ and $(x_2, y_2)$

$\text {Midpoint}(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

In the given sum, two points are (0, 2) and (6, 4)

$x_{1}=0 ; y_{1}=2 ; x_{2}=6 ; y_{2}=4$

Substituting the values in given formula,

$\begin{array}{l}{\text {Midpoint}(x, y)=\left(\frac{0+6}{2}, \frac{2+4}{2}\right)} \\\\ {\text {Midpoint }(x, y)=\left(\frac{6}{2}, \frac{6}{2}\right)=(3,3)}\end{array}$

Thus the required midpoint is (3, 3)

8 0

3 years ago

The weights of ice cream cartons are normally distributed with a mean weight of 8 ounces and a standard deviation of 0.4 ounce.

Alla [95]

Answer:

a) 0.373 probability that a randomly selected carton has a weight greater than 8.13 ounces

b) 0.097 probability that mean weight of 16 randomly selected carton is greater than 8.13 ounces

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8 ounces

Standard Deviation, σ = 0.4 ounce

We are given that the distribution of weights of ice cream cartons is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(weight greater than 8.13 ounces)

P(x > 8.13)

$P( x > 8.13) = P( z > \displaystyle\frac{8.13 - 8}{0.4}) = P(z > 0.325)$

$= 1 - P(z \leq 0.325)$

Calculation the value from standard normal z table, we have,

$P(x > 610) = 1 - 0.627 = 0.373 = 37.3\%$

b) P(weight of 16 randomly selected cartons is greater than 8.13 ounces)

P(x > 8.13)

$P( x > 8.13) = P( z > \displaystyle\frac{8.13 - 8}{\frac{0.4}{\sqrt{16}}}) = P(z > 1.3)$

$= 1 - P(z \leq 1.3)$

Calculation the value from standard normal z table, we have,

$P(x > 8.13) = 1 - 0.903 = 0.097 = 9.7\%$

5 0

3 years ago