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NISA [10]
3 years ago
7

An airplane is traveling at a speed of 200 km/h. Compute the speed of the airplane in m/s.

Mathematics
2 answers:
Nady [450]3 years ago
8 0

Given the speed is 200 km /hr


use 1 km  = 1000 meter

1 hr = 3600 seconds

so

200 km/hr = \frac{200*1000}{1*3600}   m/s

simplifies to

\frac{5000}{9} m/s

55.6 m/s

so option C

Harrizon [31]3 years ago
6 0

Answer:  C) 55.6 m/s  

Step-by-step explanation:  200km/1hr x 1000m/1km x 1hr/60min x 1min/60s = 55.6 m/s

If the conversion factors are properly set up and all numbers are correct, the unwanted units cancel out leaving the units of the final answer.

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Please help I’m on the middle of an exam<br><br> Use the diagram of ABCD to find x.
garri49 [273]

This is like property of a parallelogram you have to do is basically follow its properties which is opposite sides are congruent

so we solve like this

x+3=2x-5

subtract -3 on each side one is canceled since its equal to zero

and other is -3-5= -8

x=3x-8

now subtract -3 on each side

-3x-x is -4 so,

-4x=8

divide its equal to 2

X=2

Hope it helps! have an awesome day you should probably study the properties of parallelogram

5 0
2 years ago
Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density
seropon [69]

The charge of the electrons is 8.02 \times 10^{-19} \ C.

The given parameters:

  • <em>Number of revolution of the electron, N = 1.4 x 10⁶ rev per sec</em>
  • <em>Flux density, B = 10⁻⁵ T</em>
  • <em>Mass of electron, m = 9.11 x 10⁻³¹ kg</em>

<em />

The angular speed of the electron is calculated as follows;

\omega = 2\pi N\\\\\omega = 2\pi \ \frac{rad}{1 \ rev} \times 1.4 \times 10^6 \ rev/s\\\\\omega = 8.798 \times 10^6 \ rad/s

The charge of the electrons is calculated as follows;

F_c= m\omega ^2 r\\\\F_{B}= qvB = q\omega r B \\\\F_c = F_B\\\\m\omega ^2 r =  q\omega r B \\\\q = \frac{m\omega ^2 r}{\omega r B} \\\\q = \frac{m \omega }{B} \\\\q = \frac{9.11 \times 10^{-31} \times 8.798 \times 10^6}{10^{-5}} \\\\q = 8.02 \times 10^{-19} \ C

The charge of the electrons is 8.02 \times 10^{-19} \ C.

The complete question here:

Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density 10⁻⁵ T. What will be the value of charge of the electron?

Learn more about magnetic force of electrons here: brainly.com/question/3990732

8 0
2 years ago
The point (-3,4) is reflected across the x-axis. What is the coordinates of its new location?
Tasya [4]

Semd a pic of a graph bc I dont have paper

4 0
3 years ago
The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. find the diameter of the base of the cylinder​
White raven [17]

Answer:

2 cm

Step-by-step explanation:

h = 14 cm

Curved surface area of a right circular cylinder = 88 cm²

2πrh = 88

2 * \frac{22}{7}*r*14=88\\\\r = \frac{88*7}{2*22*14}\\\\ r =1 \\\\r = 1 cm

Diameter = 2 * r = 2 * 1 = 2  cm

6 0
3 years ago
Write an equation that you can use to solve for x.<br><br> Enter your answer in the box.
Leto [7]

Answer:

180=x+60+100

Step-by-step explanation:

Because of vertical angles the angle beside 60 is 100 and 100+60+x would equal 180 degrees

5 0
3 years ago
Read 2 more answers
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