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Agata [3.3K]
3 years ago
11

If a motorcycle is moving at a speed of 22m/s and has a mass of 375kg what is the kinetic energy

Physics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

The kinetic energy is 90750 J.

Explanation:

Given:

Mass of the motorcycle is, m=375\ kg

Velocity of the motorcycle is, v=22\ m/s

Kinetic energy of the motorcycle is given as:

KE=\frac{1}{2}mv^2

Plug in 375 for m, 22 for v and solve for kinetic energy,KE. This gives,

KE=\frac{1}{2}\times 375\times 22^2=\frac{1}{2}\times 375\times 484=90750\ J

Therefore, the kinetic energy of the motorcycle is 90750 J.

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m = 2.23 \times 10^{-32} kg

Explanation:

Given data:

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we know that

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we know that

v = \frac{2\pi R}{T}

solving for

R = \frac{vT}{2\pi}

F = \frac{Gm^2}{4(\frac{vT}{2\pi})^2}

F = G\times \frac{\pi m}{(vT)^2}

a = \frac{v^2}{\frac{vT}{2\pi}}

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we know that

f =ma

G\times \frac{\pi m}{(vT)^2} = a = \frac{2\pi m v}{T}

solving for m

m = \frac{2Tv^3}{\pi G}

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<em>0.97c</em>

<em></em>

Explanation:

From the relativistic equation for length contraction, we have

l = l_{0}\sqrt{1 - \beta }

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l is the final length of the object

l_{0} is the original length of the object before contraction

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The equation can be re-written as

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