Question

Find the net downward force on the tank's flat bottom, of area 1.60 m2 , exerted by the water and air inside the tank and the air outside the tank. Assume that the density of water is 1.00 g/cm3

Answer 1

Answer:

The net downward force on the tank is $1.85\times10^{5}\ N$

Explanation:

Given that,

Area = 1.60 m²

Suppose the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 150 K Pa , and the depth of the water will be 14.4 m . The pressure of the air in the building outside the tank will be 88.0 K Pa.

We need to calculate the net downward force on the tank

Using formula of formula

$F=(P+\rho\times g\times h-P_{out})A$

Where, P = pressure

g = gravity at mars

h = height

A = area

Put the value into the formula

$F=(150\times10^3+1.00\times10^3\times3.71\times14.4-88.0\times10^{3})\times1.60$

$F=1.85\times10^{5}\ N$

Hence, The net downward force on the tank is $1.85\times10^{5}\ N$