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3 years ago

15

Select the correct answer.

2 answers:

iren2701 [21]3 years ago

6 0

Answer:

A. The speed will increase four times.

Explanation:

If you increase the frequency of a sound wave four times, the speed will increase four times. So, option (A) is correct.

Monica [59]3 years ago

3 0

Answer:

A. The speed of the wave increases four times.

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The first law of thermodynamics invention that spurred its development is

Ket [755]

Energy and matter can neither be created or destroyed.

5 0

3 years ago

uppose that the terminal speed of a particular sky diver is 150 km/h in the spread-eagle position and 320 km/h in the nosedive p

AysviL [449]

Answer:

4.55

Explanation:

The terminal speed of a diver is given by:

$v_t=\sqrt{\frac{2mg}{C\rho A} } \\\\Where\ m=mass\ of \ driver,d=acceleration\ due\ to\ gravity,C=drag\ \\coefficient,A=cross\ sectional\ Area.\\\\Therefore:\\\\A=\frac{2mg}{C \rho v_t^2} \\\\For\ area\ with\ terminal\ speed\ in\ spread\ angle\ position(v_s):\\\\A_s=\frac{2mg}{C \rho v_s^2} \\\\For\ area\ with\ terminal\ speed\ in\ nose\ dive\ position(v_n):\\\\A_n=\frac{2mg}{C \rho v_n^2}\\\\Therefore\ since\ g,m,C,\rho\ are\ constant:\\\\$

$\frac{A_s}{A_n}= \frac{\frac{2mg}{C \rho v_s^2}}{\frac{2mg}{C \rho v_n^2}}\\\\\frac{A_s}{A_n}= \frac{v_n}{v_s} \\\\v_n=320\ km/h,v_s=150\ km/h\\\\\frac{A_s}{A_n}=\frac{320^2}{150^2} =4.55$

4 0

3 years ago

A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing i

vovangra [49]

Answer:

$c=71.4m/s$

$\theta=8.54\textdegree$

Explanation:

From the question we are told that

Initial velocity of 60 m/s

Wind speed $V_w= 15 m/s \angle 45 \textdegree$

Generally Resolving vector mathematically

$sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6$

Generally the equation Pythagoras theorem is given mathematically by

$c^2=a^2+b^2$

$c^2=10.6^2 +(10.6+60)^2$

$c=\sqrt{10.6^2 +(10.6+60)^2}$

Therefore Resultant velocity (m/s)

$c=71.4m/s$

b)Resultant direction

Generally the equation for solving Resultant direction

$\theta=tan^-1(\frac{y}{x})$

Therefore

$\theta=tan^-1(\frac{10.6}{70.6})$

$\theta=8.54\textdegree$

7 0

3 years ago

A scientist is testing the seismometer in his lab and has created an apparatus that mimics the motion of the earthquake felt in

otez555 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$a_{max} = 0.00246 \ m/s^2$

b

$k =722.2 \ N/m$

Explanation:

From the question we are told that

The amplitude is $A = 1.8 \ cm = 0.018 \ m$

The period is $T = 17 \ s$

The test weight is $W = 13 \ N$

Generally the radial acceleration is mathematically represented as

$a = w^2 r$

at maximum angular acceleration

$r = A$

So

$a_{max} = w^2 A$

Now $w$ is the angular velocity which is mathematically represented as

$w = \frac{2 * \pi }{T}$

Therefore

$a_{max} = [\frac{2 * \pi}{T} ]^2 * A$

substituting values

$a_{max} = [\frac{2 * 3.142}{17} ]^2 * 0.018$

$a_{max} = 0.00246 \ m/s^2$

Generally this test weight is mathematically represented as

$W = k * A$

Where k is the spring constant

Therefore

$k = \frac{W}{A}$

substituting values

$k = \frac{13}{0.018}$

$k =722.2 \ N/m$

7 0

4 years ago

Physical properties are Question 2 options:

anyanavicka [17]

C. those properties that cannot be changed

6 0

3 years ago